CircleHardBloom L3
Question
The line $2x - y + 1 = 0$ is tangent to the circle at the point $(2,5)$ and the centre of the circles lies on $x - 2y = 4$. The radius of the circle is:
Options
A.$3\sqrt{5}$
B.$5\sqrt{3}$
C.$2\sqrt{5}$
D.$5\sqrt{2}$
Solution
Sol. [Key Concept: Tangent at a known point + centre on a given line $\Rightarrow$ solve for the centre/radius.]
$$\begin{matrix} tan\theta & \ = \frac{2 - \frac{1}{2}}{1 + 2\left( \frac{1}{2} \right)} = \frac{3}{4} \\ \frac{r}{\sqrt{8^{2} + 4^{2}}} & \ = tan\theta = \frac{3}{4} = \frac{r}{4\sqrt{5}} \\ \Rightarrow \ r & \ = 3\sqrt{5} \end{matrix}$$
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