CircleHardBloom L3
Question
The value of $\alpha$ for which the point ( $\alpha,\alpha + 2$ ) is an interior point of smaller segment of the curve $x^{2} + y^{2} - 4 = 0$ made by the chord of the curve whose equation is $3x + 4y + 12 = 0$
Options
A.$\left( - \infty, - \frac{20}{7} \right)$
B.$( - 2,0)$
C.$\left( - \infty,\frac{20}{7} \right)$
D.$\alpha \in \phi$
Solution
[Key Concept: A point is interior to the smaller segment when $S_{1} < 0$ on the correct side of the chord — combine both conditions.]
Line does not intersect the circle
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