CircleHardBloom L3

Question

A circle with center $(2,2)$ touches the coordinate axes and a straight line $AB$ where $A$ and $B$ lie on positive direction of coordinate axes such that the circle lies between origin and the line $AB$. If $O$ be the origin then the locus of circumcenter of $\bigtriangleup OAB$ will be:

Options

A.$xy = x + y + \sqrt{x^{2} + y^{2}}$
B.$xy = x + y - \sqrt{x^{2} + y^{2}}$
C.$xy + x + y = \sqrt{x^{2} + y^{2}}$
D.$xy + x + y + \sqrt{x^{2} + y^{2}} = 0$

Solution

[Key Concept: A circle touching both axes has centre $(r,r)$; the cut-off tangent triangle uses the tangent length from the corner.]

$r = \frac{\Delta}{s} = \frac{\frac{1}{2} \times (2h)(2k)}{\frac{1}{2}\left( 2h + 2k + 2\sqrt{h^{2} + k^{2}} \right)}$

$2 = \frac{2hk}{h + k + \sqrt{h^{2} + k^{2}}}$

$ $⇒ Locus of $xy = x + y + \sqrt{x^{2} + y^{2}}$

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