Principle of Inheritance and VariationEasyBloom L3
Question
Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregation will show
Options
A.segregation in the expected 9 : 3 : 3 : 1 ratio
B.segregation in 3 : 1 ratio
C.higher number of the parental types
D.higher number of the recombinant types.
Solution
Sol.(c) [Key Concept: Linkage — Parental Types Favored] When two genes are very closely linked on the same chromosome, crossing over between them is rare. In F2 (from F1 RrYy × RrYy, but where R and Y are linked), parental gametes (RY and ry from RRYY×rryy cross) are produced in much higher frequency than recombinant gametes (Ry and rY). This results in HIGHER NUMBER OF PARENTAL TYPES (RRYY and rryy phenotypes) and fewer recombinants, NOT the standard 9:3:3:1 ratio.
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