Logic gateMedium
Question
The output Y for the given inputs A and B to the circuit is :
Options
A.
B.
C.
D.
Solution
Sol. [Key Concept: Simplify the gate output $Y = A \cdot \ B + A' \cdot \ B = (A + A')B = B$, so $Y$ simply reproduces the input-$B$ waveform.]
$$A \cdot B + \overline{A} \cdot B \Rightarrow (A + \overline{A}) \cdot B = B $$Note: In lower gate, input is taken from A as $\overline{A}$ due to node given in the figure.
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