Question
Given below are two statements:
Statement-I: Due to increase in van der Waals forces, the order of boiling points is ${CH}_{3}{CH}_{2}{CH}_{2}I > {CH}_{3}{CH}_{2}I > {CH}_{3}I$.
Statement-II : As 
is more symmetric, its melting point is higher than
, however, its boiling point is lower than
In the light of the above statements, choose the correct answer from the options given below:
Options
Solution
Sol. [Key Concept: Boiling point rises with molecular mass and van der Waals forces (Statement I true); the more symmetric $p$-dichlorobenzene packs better giving a higher melting point, yet its zero dipole gives a lower boiling point than the $o$-isomer (Statement II true).]
Statement I : True
Order of boiling point :
$${CH}_{3}{CH}_{2}{CH}_{2}I > {CH}_{3}{CH}_{2}I > {CH}_{3}I $$Vanderwaals forces increases due to increase in molecular weight
Statement 2: True
Order of melting point :- 
Boiling point order :-
(Boiling point $\propto \mu$ )
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