The energy released if hydrogen atoms are combined to form $\frac{4}{2}He$ is $\_\_\_\_$ .(Take bind

Question

The energy released if hydrogen atoms are combined to form $\frac{4}{2}He$ is $\_\_\_\_$ .(Take binding energies per nucleon of $\ _{1}^{2}H$ and $\ _{2}^{4}He$ as 1.1 meV and 7.2 MeV , respectively).

Accepted Answer

Sol. [Key Concept: Fusion $2H + {}^{2}H ightarrow {}^{4}He$: $Q = BE(He) - 2\ BE(^{2}H) = 4 	imes 7.2 - 4 	imes 1.1 = 24.4$ MeV.]$$\ \ _{1}^{2}H + \overline{\ _{1}^{2}H ightarrow \ _{2}^{4}He} $$$Q = BE$ (RHS) -BE (LHS)$${= 4 	imes 7.2 - 4 	imes 1.1 }{= 4 	imes 6.1 }$$Q $= 24.4MeV$

Question

Options

Solution

More Nuclear Physics and Radioactivity Questions