Aromatic HydrocarbonsMedium
Question
Consider the following reactions. Total number of electrons in the $\pi$ bonds and lone pair of electrons in the product ( X ) is:
Options
A.12
B.16
C.14
D.18
Solution
Sol. [Key Concept: Reduce the sugar acid with HI to $n$-hexane, aromatise over $V_{2}O_{5}$ to benzene, then Friedel-Crafts benzoylation gives benzophenone; count its $\pi$-bond and lone-pair electrons $= 18$.]
Total number of $\pi$ and lone pair electrons in final product $= 18$
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