Carbonyl CompoundMedium
Question
An optically active alkyl bromide $C_{4}H_{9}Br$, reacts with ethanolic KOH to form major compound [A] which reacts with bromine to give compound [B]. Compound [B] reacts with ethanolic KOH and sodamide to give compound [C]. One molecule of water adds to compound [C] on warming with mercuric sulphate and dilute sulphuric acid at 333 K to form compound [D]. The functional group in compound D will be confirmed by:
Options
A.Haloform test
B.Lucas test
C.Silver mirror test
D.Benedict test
Solution
Sol. [Key Concept: Follow the sequence alkyl bromide $\rightarrow$ alkene $\rightarrow$ dibromide $\rightarrow$ alkyne $\rightarrow$ methyl ketone; the terminal methyl ketone (compound D) is confirmed by the haloform (iodoform) test.]
Final product gives + ve haloform test
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