Question
Which of the following sequence of hybridization, geometry and magnetic nature are correct for the given coordination compounds?
A. $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -} - {sp}^{3}$, tetrahedral, paramagnetic
B. $\left\lbrack Ni\left( {NH}_{3} \right)_{6} \right\rbrack^{2 +} - {sp}^{3}{\text{ }d}^{2}$, octahedral, paramagnetic
C. $\left\lbrack Ni(CO)_{4} \right\rbrack - {sp}^{3}$, tetrahedral, paramagnetic
D. $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -} - {dsp}^{2}$, square planar diamagnetic
Choose the correct answer from the options given below:
Options
Solution
Sol. [Key Concept: Check each Ni complex: $\lbrack Ni(CO)_{4}\rbrack$ is ${sp}^{3}$, tetrahedral and diamagnetic (not paramagnetic), so statement C is wrong and A, B, D are correct.]
$\left\lbrack Ni(CO)_{4} \right\rbrack$ is ${sp}^{3}$, tetrahedral and diamagnetic
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