Electromagnetic WavesMedium
Question
A point light source emits E.M. waves in free space. A detector, placed at a distance of L m , measures the intensity as $I_{0}$. The detector is now shifted to another location on the same spherical surface ensuring the angle between original location and new location as $45^{\circ}$. The measured intensity at new location will be $\_\_\_\_$ .
Options
A.$\frac{I_{0}}{4}$
B.$I_{0}$
C.$\frac{I_{0}}{\sqrt{2}}$
D.$\frac{I_{0}}{2}$
Solution
Sol. [Key Concept: Both detector positions lie on the same spherical surface (same distance from the source), so $I = \frac{P}{4\pi\ R^{2}}$ is unchanged, $= I_{0}$.]
Distance is same
So intensity is also same
$$I = \frac{P}{4\pi R^{2}} $$
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