Assuming the experimental mass of $\ _{6}^{12}C$ as 12 u , the mass defect of $\ _{6}^{12}C$ atom is

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Assuming the experimental mass of $\ _{6}^{12}C$ as 12 u , the mass defect of $\ _{6}^{12}C$ atom is __ $MeV/c^{2}$. (Mass of proton $= 1.00727u$. mass of neutron $= 1.00866u,1u = 931.5MeV/c^{2}$ and c is the speed of the light in vacuum.)

Accepted Answer

Sol. [Key Concept: Mass defect $\Delta\ m = (6m_{p} + 6m_{n}) - 12\ u$; convert with $1\ u = 931.5$ MeV/$c^{2}$.]$${\Delta m = \left( 6{	ext{ }m}_{p} + 6{	ext{ }m}_{n} ight) - m_{c} }{= 6(1.00727 + 1.00866) - 12 }{= 0.09558amu = 89.03MeV/C^{2} }$$

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