In Young's double slit experiment, the frings width of the interferences pattern produced on the scr

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In Young's double slit experiment, the frings width of the interferences pattern produced on the screen is $2.4\mu	ext{ }m$. If the experiment is carried out in another medium having refractive index 1.2, the fringe width will be $\_\_\_\_$ $\mu m$.

Accepted Answer

Sol. [Key Concept: In a medium the fringe width shrinks: $\beta' = \frac{\beta}{\mu}$.]Since Fringe width in a medium becomes$$\begin{matrix} \beta^{'} = \frac{\beta}{\mu} & \left( 	ext{~}	ext{Here}	ext{~}\beta = \frac{\lambda D}{d} ight) \ \beta^{'} = \frac{\beta}{\mu} = \frac{2.4}{1.2} = 2\mu	ext{ }m & \end{matrix}$$

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