HydrocarbonsMedium
Question
Compound ( X ) is subjected to the sequence of reactions as shown above. Molar mass of the major product (Y) formed is $\_\_\_\_$ ${gmol}^{- 1}$.
(Given molar mass in $g{mol}^{- 1}C:12,H:1,O:16$ )
Options
A.90
B.118
C.160
D.125
Solution
Sol. [Key Concept: Follow the sequence: bromination, NaNH$2$ elimination, CH$3$I alkylation, then Na/liq.NH$3$ to the trans-alkene $C_{9}H_{10}$ ($M = 118$).]
Molar mass of $Y = 118gm$
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