Carbonyl CompoundMedium
Question
Given below are two statements:
Statement-I : The condensation reaction between ${CH}_{3} - CH = O$ and 
under optimum pH will produce 
Statement-II : The molecule, 
will generate $Ph - CH = O$ in the presence of dilute acid.
In the light of the above statements, choose the correct answer from the options given below:
Options
A.Both Statement-I and Statement-II are true.
B.Both Statement-I and Statement-II are false.
C.Statement-I is true but Statement-II is false.
D.Statement-I is false but Statement-II is true.
Solution
Sol. [Key Concept: Semicarbazide attacks the carbonyl through its more nucleophilic terminal $- {NH}_{2}$; the acetal $Ph - CH(OH)({OCH}_{3})$ hydrolyses in dilute acid to $Ph - CHO$ (statement-II true, statement-I false).]
Statement-I
Hence statement-I is incorrect.
Statement-II
Statement-II is correct.
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