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Question

Consider a circuit consisting of a capacitor $(20\mu\text{ }F)$, resistor ( $100\Omega$ ) and two identical diodes as shown in figure. The resistance of diode under forward biasing condition is $10\Omega$. The time constant of the circuit is $\alpha \times 10^{- 3}\text{ }s$. The value of $\alpha$ is $\_\_\_\_$ .

Options

A.2.2
B.2.0
C.2.1
D.2.4

Solution

Sol. [Key Concept: Under forward bias the charging resistance is $R + r_{diode} = 110\ \Omega$; $\tau = RC$ gives $\alpha$.]

$${\tau = RC }{\tau = (110) \times 20 \times 10^{- 6}\sec }{\tau = 2200 \times 10^{- 6}\sec }{\tau = 2.2 \times 10^{- 3}\sec }$$

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