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Question

Match the List-I with List-II

List-I

Complex ion

List-II

Calculated spin only

magnetic moment (BM)
A. $$\left\lbrack Cr\left( H_{2}O \right)_{6} \right\rbrack^{2 +}$$ I. 3.87
B. $$\left\lbrack Co\left( H_{2}O \right)_{6} \right\rbrack^{2 +}$$ II. 5.92
C. $$\left\lbrack Cu\left( H_{2}O \right)_{6} \right\rbrack^{2 +}$$ III. 4.90
D. $$\left\lbrack Mn\left( H_{2}O \right)_{6} \right\rbrack^{2 +}$$ IV. 1.73


Choose the correct answer from the options given below:

Options

A.A-I, B-III, C-IV, D-II
B.A-II, B-I, C-III, D-IV
C.A-IV, B-II, C-I, D-III
D.A-III, B-I, C-IV, D-II

Solution

Sol. [Key Concept: Count unpaired electrons in each aqua complex, then $\mu = \sqrt{n(n + 2)}$ BM, and match.]

$\left\lbrack Cr\left( H_{2}O \right)_{6} \right\rbrack^{2 +} \rightarrow 4$ unpaired $e^{-}$; 4.90 BM(III)

$\left\lbrack Co\left( H_{2}O \right)_{6} \right\rbrack^{2 +} \rightarrow 3$ unpaired $e^{-};3.87BM(I)$

$\left\lbrack Cu\left( H_{2}O \right)_{6} \right\rbrack^{2 +} \rightarrow 1$ unpaired $e^{-};1.73BM(IV)$

${\ \lbrack Mn\left( H_{2}O \right)_{6}\rbrack}^{2 +} \rightarrow 5$ unpaired $e^{-};5.92\ BM(IV $

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