In order to oxidise a mixture of 1 mole each of ${FeC}_{2}O_{4},{Fe}_{2}\left( C_{2}O_{4} \right)_{3

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In order to oxidise a mixture of 1 mole each of ${FeC}_{2}O_{4},{Fe}_{2}\left( C_{2}O_{4} \right)_{3},{FeSO}_{4}$ and ${Fe}_{2}\left( {SO}_{4} \right)_{3}$ in acidic medium, the number of moles of ${KMnO}_{4}$ required is :

Accepted Answer

Sol. [Key Concept: Equivalents of ${KMnO}_{4} = \sum$ equivalents of the reductants; moles $	imes 5 =$ total milli-equivalents.]Meq of ${KM}_{n}O_{4} = meq$ of ${FeC}_{2}O_{4} + meq$ of ${Fe}_{2}\left( C_{2}O_{4} ight) +$ meq of ${FeSO}_{4}$moles $	imes 5 = 1 	imes 3 + 1 	imes 6 + 1 	imes 1$moles $= \frac{10}{5} = 2$

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