Fluid MechanicsMediumBloom L3
Question
A vessel filled with a liquid of density ρ falls vertically downwards with an acceleration a (< g). The pressure P at depth h below the free surface of the liquid is
Options
A.P = ρh(g + a)
B.P = ρhg
C.P = ρh(g − a)
D.P = ρha
Solution
For the falling vessel F1 + mg − F2 = ma, so F1 − F2 = m(g − a) and therefore P2 − P1 = ρh(g − a).
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