Coordination CompoundHardBloom L1

Question

Select incorrect statement(s) for [Cu(CN)4]3–, [Cd(CN)4]2– and [Cu(NH3)4]2+ complex ion.

Options

A.Both [Cd(CN)4]2– and [Cu(NH3)4]2+ have square planar geometry
B.[Cu(CN)4]3– and [Cu(NH3)4]2+ have equal no. of unpaired electron
C.[Cu(CN)4]3– and [Cd(CN)4]2– can be separated from the mixture on passing H2S gas.
D.All the three complexes have magnetic moment equal to zero.

Solution

Sol. [Cu(CN)4]–3 [Cd(CN)4]–2 [Cu(NH3)4]+2

Oxidation state of Cu ⇒ +1 Oxidation state of Cd ⇒+2 Oxidation state fo Cu ⇒ +2

Cu+ ⇒ 3d10 Cd+2 ⇒ 4d10 Cu+2 ⇒ 3d9

geometry ⇒ Tetrahedral geometry ⇒ Tetrahedral geometry ⇒ square planar

hybridization ⇒ sp3 hybridization ⇒ sp3 hybridization ⇒ dsp2.

Magnetic nature ⇒ magnetic nature ⇒ magnetic nature ⇒

diamagnetic diamagnetic paramagnetic

[Cu(CN)4]–3 + H2S → × (No reaction)

[Cd(CN)4]–2 + H2S → $\underset{(yellow)}{CdS \downarrow}$

“[Cu(CN)4]–2 act as perfect while [Cd(CN)4]–2 act as imperfect”

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