Coordination CompoundHardBloom L3

Question

[Cr(H2O)6]Cl3 (atomic number of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the chromium present in the complex is:

Options

A.3d1xy, 3d1yz, 3d1zx
B.3d1xy, 3d1yz, $3{d^{1}}_{z^{2}}$
C.$3{d^{1}}_{(x^{2} - y^{2})},3{d^{1}}_{z^{2}}3{d^{1}}_{xz}$
D.$3{d^{1}}_{xy},3{d^{1}}_{(x^{2} - y^{2})},3{d^{1}}_{yz}$

Solution

Sol. [Cr(H2O)6]Cl3 ⇒ Cr+3 = 3d3 ; μ = 3.83 B.M

$3d_{xy}^{1}3d_{yz}^{1}3d_{zx}^{1}$

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