Wave motionHardBloom L3
Question
An string has resonant frequencies given by 1001 Hz and 2639 Hz.
Options
A.If the string is fixed at one end only, 910 Hz can be a resonance frequency.
B.If the string is fixed at one end only, 1911 Hz can be a resonance frequency.
C.If the string is fixed at both the ends, 364 Hz can be one of the resonant frequency.
D.1001 Hz is definitely not the fundamental frequency of the string.
Solution
Sol. (B) String fixed at one end
⇒ f = (2n + 1)f0
for f0 = 91
⇒ 1001 = 11f0, 1911 = 21f0, 2639 = 29f0
(C) String fixed at both ends
f = nf0
for f0 = 91
⇒ 364 = 4f0, 1001 = 11f0, 2639 = 29f0
(D) If 1001 Hz is F.F. then 2639 should be multiple of 1001, which is not.
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