Wave motionHardBloom L3

Question

If the tension in a stretched string fixed at both ends is changed by 20%, the fundamental frequency is found to increase by 15Hz. then the

Options

A.original frequency is 157 Hz
B.velocity of propagation of the transverse wave along the string changes by 5%
C.velocity of propagation of the transverse wave along the string changes by 10%.
D.fundamental wave length on the string does not change.

Solution

Sol. v = $\sqrt{\frac{T}{\mu}}$

v' = $\sqrt{\frac{1.2T}{\mu}}$ = v$\sqrt{1.2}$ = 1.095 v≅ 1.1 v

f0 = $\frac{v}{2L}$

f0' = 1.095 f0

⇒∆f = 0.095 f0

For fundamental mode

L = $\frac{\lambda}{2}$

⇒λ = 2L, L does not change, hence λ

Create a free account to view solution

View Solution Free
Topic: Wave motion·Practice all Wave motion questions

More Wave motion Questions

Standing waves are produced in 10 m long streched string If the string vibrates in 5 segments and wave velocity is 20m/s...Y(x,t) = 0.05 / [(4x + 2t)2 + 5] represents a moving wave pulse, where x and y are in meters and t is in seconds. Then w...The energy in the phenomenon of interference :...If the resultant intensity due to superposition of two waves of amplitude 3 & 4 in opposite phase is 1 if wave of amplit...The (x , y) co-ordinates of the corners of a square plate are (0, 0) (L, 0) (L, L) & (0, L). The edges of the plate ...