Wave motionMediumBloom L3
Question
A taut string at both ends vibrates in its nth overtone. The distance between adjacent Node and Antinode is found to be ‘d’. If the length of the string is L, then
Options
A.L = 2d (n + 1)
B.L = d (n + 1)
C.L = 2dn
D.L = 2d (n – 1)
Solution
Sol. $\frac{\lambda}{4} = d$
⇒ λ = 4d
nth overtone ⇒ (n + 1) loops
⇒ L = (n + 1)$\frac{\lambda}{2}$ = 2d (n + 1)
Create a free account to view solution
View Solution FreeMore Wave motion Questions
If the velocity of wave is 360 m/s and frequency is 50 Hz determine the path diference corrosponding to 60° phase diff.I...A transverse wave is propagating along +x direction. At t=2 sec, the particle at x=4m is aty=2 mm.With the passage of ti...The (x, y) coordinates of the corner of a square plate are (0, 0), (L, 0), (L, L) and (0, L). The edge of the plate are ...When a string is divided into three segments of length l1, l2 and l3, the fundamental frequencies of thesethree segments...If the tension in a stretched string fixed at both ends is changed by 20%, the fundamental frequency is found to increas...