Wave motionHardBloom L3
Question
A taut string at both ends vibrates in its nth overtone. The distance between adjacent Node and Antinode is found to be ‘d’. If the length of the string is L, then
Options
A.L = 2d (n + 1)
B.L = d (n + 1)
C.L = 2dn
D.L = 2d (n – 1)
Solution
Sol. $\frac{\lambda}{4} = d$
⇒ λ = 4d
nth overtone ⇒ (n + 1) loops
⇒ L = (n + 1)$\frac{\lambda}{2}$ = 2d (n + 1)
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