Wave motionMediumBloom L3

Question

The prong of a electrically operated tuning fork is connected to a long string of μ = 1 kg/m and tension 25 N. The maximum velocity of the prong is 1 cm/s, then the average power needed to drive the prong is:

Options

A.5 × 10–4 W
B.2.5 × 10–4 W
C.1 × 10–4 W
D.10–3 W

Solution

Sol. Pavg = $\frac{1}{2}µ(A\omega)^{2}v$

= $\frac{1}{2} \times 1(1 \times 10^{- 2})^{2} \times \sqrt{\frac{25}{2}}$

= 2.5 × 10–4 W

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