Wave motionHardBloom L3

Question

The displacement from the position of equilibrium of a point 4 cm from a source of sinusoidal oscillations is half the amplitude at the moment t = T/6 (T is the time period). Assume that the source was at mean position at t = 0. The wavelength of the running wave is

Options

A.0.96 m
B.0.48 m
C.0.24 m
D.0.12 m

Solution

Sol. y = Asin (ωt – kx)

At x = 4cm, t = T/6, y = A/2

$\frac{A}{2} = A\sin\left\lbrack \frac{2\pi}{T}\left( \frac{T}{6} \right) - k\left( \frac{4}{100} \right) \right\rbrack$

sin$\left\lbrack \frac{\pi}{3} - k\left( \frac{4}{100} \right) \right\rbrack = \frac{1}{2}$

$\frac{\pi}{3} - \frac{4k}{100} = \frac{\pi}{6}$

$\frac{4k}{100} = \frac{\pi}{6}$

$k = \frac{2\pi}{\lambda} = \frac{100\pi}{24}$

$\lambda = \frac{48}{100}m = 48cm$

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