Wave motionMediumBloom L3
Question
A wave is propagating along x-axis. The displacement of particles of the medium in z-direction at t = 0 is given by: z = exp[ –(x + 2)2] , where ‘x’ is in meters. At t = 1s, the same wave disturbance is given by: z = exp[ – (2 – x)2 ]. Then, the wave propagation velocity is
Options
A.4 m/s in + x direction
B.4 m/s in –x direction
C.2 m/s in + x direction
D.2 m/s in – x direction
Solution
Sol. Let z = exp [–(x – vt + 2)2]
Put t = 1s, z = exp [– (x –v + 2)2]
Comparing with given equation
⇒ x – v + 2 = x – 2
⇒ v = + 4m/s
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