The difference between the apparent frequencies of a sound source as perceived by a stationary obser

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The difference between the apparent frequencies of a sound source as perceived by a stationary observer during its approach and recession is 2% of the actual frequency of the source. The speed of source is (Speed of sound = 300 m/s)

Accepted Answer

Sol. f1 = $\left( \frac{v}{v - v_{s}} ight)f_{0}$f2 = $\left( \frac{v}{v + v_{s}} ight)f_{0}$$\frac{f_{1} - f_{2}}{f_{0}}$ = 2% = $\left( \frac{v}{v - v_{s}} - \frac{v}{v + v_{s}} ight)$⇒ $\frac{2}{100} = \left( \frac{2vv_{s}}{v^{2} - v_{s}^{2}} ight)$⇒ $\frac{2}{100} = \frac{2 	imes 300v_{s}}{(300)^{2} - v_{s}^{2}}$⇒ $v_{s} \cong 3m/s$

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