Sound WavesHardBloom L3
Question
If l1 and l2 are the lengths of air column for the first and second resonance when a tuning fork of frequency n is sounded on a resonance tube, then the distance of the displacement antinode from the top end of the resonance tube is:
Options
A.2(l2 – l1)
B.$\frac{1}{2}$ (2l1 – l2)
C.$\frac{l_{2} - 3l_{1}}{2}$
D.$\frac{l_{2} - l_{1}}{2}$
Solution
Sol. f = $\frac{\nu}{4(l_{1} + e)}$ (considering end correction)
Also f = $\frac{3\nu}{4(l_{2} + e)}$
⇒ $\frac{4(l_{2} + e)}{3}$ = 4(l1 + e)
⇒ l2 + e = 3l1 + 3e
⇒ l2–3l1 =2e
⇒ e = $\frac{l_{2} - 3l_{1}}{2}$
Create a free account to view solution
View Solution FreeMore Sound Waves Questions
Two identical piano wires, kept under the same tension T have a fundamental frequency of 600 Hz. The frictional increase...A plane transverse wave is propagating in a direction making an angle of 30° with positive x-axis in the x-y plane. Find...If y1 = 5 (mm) sinπt is equation of oscillation of source S1 and y2 = 5 (mm) sin (πt + π / 6) be that of ...An object of spcific gravity ρ is hung from a thin steel wire. he findamental frequency for transervse standing wav...Two sound waves, having sinusoidal waveform but different wavelength and different amplitude, are said to have...