Momentum and CollisionHardBloom L3
Question
Two uniform non conducting balls A & B have identical size having radius R but made of different density material (density of A = 2 density of B). The ball A is +vely charged & ball B is –vely charged. The balls are released on the horizontal smooth surface at the separation 10R as shown in figure. Because of mutual attraction the balls start moving towards each other. They will collide at a point.
Options
A.x = $\frac{10R}{3}$
B.x = $\frac{11R}{3}$
C.x = 5R
D.x = $\frac{7R}{5}$
Solution
Sol. 
$x_{cm} = \frac{2m.0 + m.10R}{3m}$
fext = 0 ⇒ acm = 0 ⇒ vcm = constant = 0
⇒ (∆x)cm = 0
∴ Distance of A = XCOM + (R – d) = $\frac{10R}{3} + \left( R - \frac{2R}{3} \right) = \frac{11R}{3}$
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