Momentum and CollisionHardBloom L3
Question
A system of two blocks A and B are connected by an inextensible massless string as shown. The pulley is massless and frictionless. Initially the system is at rest when, a bullet of mass 'm' moving with a velocity 'u' as shown hits the block 'B' and gets embedded into it. The impulse imparted by tension force to the block of mass 3m is
Options
A.$\frac{5mu}{4}$
B.$\frac{4mu}{5}$
C.$\frac{2mu}{5}$
D.$\frac{3mu}{5}$
Solution
Sol. Writing Impulse equation for tension
–Tdt = (m + m) v – mv .....(1)
Tdt = 3mv – 0 .....(2)
⇒ 5mv = mu
⇒ v = $\frac{u}{5}$
⇒ Impulse by tension on 3m = $3m\left( \frac{u}{5} \right)$ = $\frac{3mu}{5}$
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