Center of MassMediumBloom L3
Question
From the circular disc of radius 4R two small disc of radius R are cut off. The center of mass of the new structure will be:
Options
A.$i\frac{R}{5} + j\frac{R}{5}$
B.$- i\frac{R}{5} + j\frac{R}{5}$
C.$\frac{- 3R}{14}(\widehat{i} + \widehat{j})$
D.None of these
Solution
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