A nucleus has mass number $\alpha$ and radius $R_{\alpha}$. Another nucleus has mass number $\beta$

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A nucleus has mass number $\alpha$ and radius $R_{\alpha}$. Another nucleus has mass number $\beta$ and radius $R_{\beta}$. If $\beta = 8\alpha$ then $R_{\alpha}/R_{\beta}$ is :

Accepted Answer

$R_{\alpha} = R_{0}\alpha^{1/3}$$${R_{\beta} = R_{0}\beta^{1/3} }{\frac{R_{\alpha}}{R_{\beta}} = \left( \frac{\alpha}{\beta} \right)^{1/3} = \frac{1}{2}}$$

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