Binomial TheoremHard
Question
$\frac{6}{3^{26}} + \frac{10.1}{3^{25}} + \frac{10.2}{3^{24}} + \frac{{10.2}^{2}}{3^{23}} + \ldots + \frac{{10.2}^{24}}{3}$ is equal to
Options
A.$2^{25}$
B.$2^{26}$
C.$3^{25}$
D.$3^{26}$
Solution
$\ S = \frac{6}{3^{26}} + \frac{10}{3^{25}}\left\lbrack \frac{(6)^{25} - 1}{6 - 1} \right\rbrack$
$$\begin{matrix} & S = \frac{6}{3^{26}} + \frac{10}{3^{25}}\left\lbrack \frac{6^{25} - 1}{5} \right\rbrack \\ & S = \frac{2}{3^{25}} + 2\left\lbrack 2^{25} - \frac{1}{3^{25}} \right\rbrack \\ & S = 2^{26} \end{matrix}$$
Create a free account to view solution
View Solution FreeMore Binomial Theorem Questions
The (m + 1)th term of is :...If ′a′ be the sum of the odd terms & ′b′ be the sum of the even terms in the expansion of (1 + x...If an = , then equals -...If n = 11 then (C02 − C12 + C22 − C32 +.....+ (−1)n (Cn2) equals-...The number of values of ′r′ satisfying the equation, 39C3r-1 - 39Cr2 = 39Cr2-1 - 39C3r is...