Set, Relation and FunctionHard

Question

Given below are two statements:

Statement I: The function $f:\mathbf{R} \rightarrow \mathbf{R}$ defined by $f(x) = \frac{x}{1 + |x|}$ is one-one.

Statement II : The function $f:\mathbf{R} \rightarrow \mathbf{R}$ defined by $f(x) = \frac{x^{2} + 4x - 30}{x^{2} - 8x + 18}$ is many-one.

In the light of the above statements, choose the correct answer from the options given below :

Options

A.Both Statement I and Statement II are false.
B.Both Statement I and Statement II are true.
C.Statement I is false but Statement II is true .
D.Statement I is true but Statement II is false.

Solution

Statement 1: $f(x) = \frac{x}{1 + |x|}$

$$f(x) = \left\{ \begin{matrix} \frac{x}{1 + x} & x \geq 0 \\ \frac{x}{1 - x} & x < 0 \end{matrix} \right.\ $$

$f(x)$ is one-one

Statement 2: $f(x) = \frac{x^{2} + 4x - 30}{x^{2} - 8x + 18},f(0) = \frac{- 30}{18} = \frac{- 5}{3}$

$$\frac{- 5}{3} = \frac{x^{2} + 4x - 30}{x^{2} - 8x + 18} $$On solving $x = 0, - 1$

$$\Rightarrow f(0) = f( - 1) = \frac{- 5}{3} $$$\therefore f(x)$ is many-one

Create a free account to view solution

View Solution Free
Topic: Set, Relation and Function·Practice all Set, Relation and Function questions

More Set, Relation and Function Questions