Purification and characteristic of organic compounMedium
Question
A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of sulphur present in the compound is $\_\_\_\_$ .
(Given Molar mass in $g{mol}^{- 1}\text{ }S:32,{BaSO}_{4}:233$ )
Options
A.$42.10\%$
B.$63.15\%$
C.$21.05\%$
D.$48.24\%$
Solution
%S $= \frac{32}{233} \times \frac{0.4813}{0.314} \times 100$
$$= 21.052\%$$
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