Question
Consider the following reactions.$ $$${{Na}_{2}{\text{ }B}_{4}O_{7}\overset{\phantom{\Delta\ }}{\rightarrow}2X + Y }{{CuSO}_{4} + Y\overset{\phantom{\text{~}\text{Non-Luminous flame}\text{~}\ }}{\rightarrow}Z + {SO}_{3} }$$$2Z + 2X +$ Carbon $\overset{\phantom{\text{~}\text{Luminous flame}\text{~}\ }}{\rightarrow}2Q + {Na}_{2}{\text{ }B}_{4}O_{7} + CO$
The oxidation states of Cu in Z and Q , respectively are :
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Solution
$\ {Na}_{2}{\text{ }B}_{4}O_{7}\overset{\phantom{\Delta\ }}{\rightarrow}\left( 2{NaBO}_{2} \right) + B_{2}O_{3}$
$${{CuSO}_{4} + B_{2}O_{3}\underset{\phantom{\text{~}\text{Non-Luminous flame}\text{~}\ }}{\overset{\phantom{\Delta\ }}{\rightarrow}}\underset{\begin{matrix} \text{~}\text{(Blue bead)}\text{~} \\ \text{~}\text{(Z)}\text{~} \end{matrix}}{+ 2} + {SO}_{3} }{2Cu\left( {BO}_{2} \right)_{2} + 2{NaBO}_{2} + C\underset{\phantom{\text{~}\text{Lumin ous Flame}\text{~}\ }}{\overset{\phantom{\Delta\ }}{\rightarrow}} }{2\underset{\begin{matrix} \text{~}\text{Colorless}\text{~} \\ (Q) \end{matrix}}{\overset{+ 1}{Cu}}{BO}_{2} + {Na}_{2}{\text{ }B}_{4}O_{7} + CO}$$
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