ElectrostaticsMedium
Question
Two-point charges of 1 nC and 2 nC are placed at the two corners of equilateral triangle of side 3 cm . The work done in bringing a charge of 3 nC from infinity to the third corner of the triangle is
$\_\_\_\_$ $\mu J$.
$$\frac{1}{4\pi\epsilon_{0}} = 9 \times 10^{9}\text{ }N.m^{2}/C^{2}$$
Options
A.2.7
B.5.4
C.3.3
D.27
Solution
$${\left( q_{2} \right) }{W = \left( \frac{{kq}_{1}}{\mathcal{l}} + \frac{{kq}_{2}}{\mathcal{l}} \right)q_{3} }{= \frac{9 \times 10^{9}}{3 \times 10^{- 2}}\left( 3 \times 10^{- 9} \right) \times 3 \times 10^{- 9} }{= 27 \times 10^{- 7}\text{ }J = 2.7\mu\text{ }J}$$
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