$Ph - CH = {CH}_{2}\underset{\phantom{HBr\ }}{\overset{\phantom{(PhCOO)_{2}\ }}{\rightarrow}}$ Produ

Question

$Ph - CH = {CH}_{2}\underset{\phantom{HBr\ }}{\overset{\phantom{(PhCOO)_{2}\ }}{\rightarrow}}$ Product

Consider the above reaction

A. The reaction proceeds through a more stable radical intermediate.

B. The role of peroxide is to generate $\overset{˙}{H}$ (Hydrogen radical).

C. During this reaction, benzene is formed as a biproduct.

D. 1-Bromo-2-phenylethane is fanned as the minor product.

E. The same reaction in absence of peroxide proceeds via carbocation intermediate.

Identify the correct statements. Choose the correct answer from the options given below:

Accepted Answer

$Ph - CH = {CH}_{2}\underset{\phantom{HBr\ }}{\overset{\phantom{(PhCOO)_{2}\ }}{\rightarrow}}Ph - {CH}_{2} - {CH}_{2} - Br$

Anti Markovnikov addition

Reaction follow radical addition in presence of peroxide

In absence of peroxide follow carbocation mechanism

Benzene also formed

Question