General Organic ChemistryMedium

Question

CORRECT order of stability for the following is ${CH}_{2} = {CH}^{-},{CH}_{3} - {CH}_{2}^{-},CH \equiv C^{-}$

Options

A.${CH}_{3} - {CH}_{2}^{-} > {CH}_{2} = {CH}^{-} > CH \equiv C^{-}$
B.${CH}_{2} = {CH}^{-} > CH \equiv C^{-} > {CH}_{3} - {CH}_{2}^{-}$
C.$CH \equiv C^{-} > {CH}_{2} = {CH}^{-} > {CH}_{3} - {CH}_{2}^{-}$
D.$CH \equiv C^{-} > {CH}_{3} - {CH}_{2}^{-} > {CH}_{2} = {CH}^{-}$

Solution

${CH}_{2} = C\overline{H}{CH}_{3} = C{\overline{H}}_{2}\ CH \equiv \overline{C}$

Stability $\propto \%\text{ }S$

Order of stability

$$CH \equiv \overline{C} > {CH}_{2} = C\overline{H} > {CH}_{3} - C{\overline{H}}_{2}$$

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