Wave OpticsMedium
Question
In the Young's double slit experiment the intensity produced by each one of the individual slits is $I_{0}$. The distance between two slits is 2 mm . The distance of screen from slits is 10 m . The wavelength of light is $6000\text{Å}$. The intensity of light on the screen in front of one of the slits is $\_\_\_\_$ .
Options
A.$2I_{0}$
B.$I_{0}$
C.$\frac{I_{0}}{2}$
D.$4I_{0}$
Solution
$d = 2\text{ }mm$
$${D = 10\text{ }m }{\lambda = 6000\text{Å} }$$$y = \frac{d}{2}($ in front of one slit $)$
$${I = 4I_{0}\cos^{2}\left( \frac{2\pi}{\lambda} \cdot \frac{y}{D}d \right) }{\Rightarrow I = I_{0}}$$
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