Fluid MechanicsHard

Question

A cubical block of density $\rho_{b} = 600\text{ }kg/m^{3}$ floats in a liquid of density $\rho_{e} = 900\text{ }kg/m^{3}$. If the height of block is $H = 8.0\text{ }cm$ then height of the submerged part is $\_\_\_\_$ cm .

Options

A.7.3
B.4.3
C.6.3
D.5.3

Solution

$Mg = F_{b}$

$$\begin{matrix} & dAHg = \rho Ahg \\ & 600 \times 8\text{ }cm = 900 \times h \\ & \text{ }h = \frac{16}{3}\text{ }cm \\ & \text{ }h = 5.3\text{ }cm \end{matrix}$$

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