Sound WavesHard
Question
The fifth harmonic of a closed organ pipe is found to be in unison with the first harmonic of an open pipe. The ratio of lengths of closed pipe to that of the open pipe is $5/x$. The value of x is $\_\_\_\_$ .
Options
A.4
B.2
C.1
D.3
Solution
$\ f_{5\text{~closed~}} = f_{1\text{~open~}}$
$${\frac{5v}{4{\text{ }L}_{\text{closed~}}} = \frac{v}{2{\text{ }L}_{\text{open~}}} }{\frac{L_{\text{closed~}}}{L_{\text{open~}}} = \frac{5}{2} }{x = 2}$$
Create a free account to view solution
View Solution FreeMore Sound Waves Questions
A radar has a power of 1 kW and is operatingat a frequency of 10 GHz. It is located on amountain top of height 500 m. Th...A transverse wave passes through a string with the equation : y = 10sin π(0.02x - 2.00t) where x is in matre and t ...The speed of longitudinal wave is 100 times the speed of transverse wave in a taut brass wire. If the Young’s modulus of...Two waves y1 = Acos(0.5 πx - 100πt) and y2 = Acos(0.46 πx - 92 πt)are travelling in a pipe placed al...In a wave motion y = a sin(kx - ωt), y can represents...