The exit surface of a prism with refractive index $n$ is coated with a material having refractive in

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The exit surface of a prism with refractive index $n$ is coated with a material having refractive index $\frac{n}{2}$. When this prism is set for minimum angle of deviation it exactly meets the condition of critical angle. The prism angle is

Accepted Answer

$i = e\& r = A/2$ for minimum deviationFor TIR ; $r = 	heta_{C}$$${Sinr = Sin	heta_{C} }{Sinr = \frac{n/2}{n} }{Sinr = \frac{1}{2} }{Sin\frac{A}{2} = sin30^{\circ} }{\frac{A}{2} = 30^{\circ} }{A = 60^{\circ}}$$

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