Quadratic EquationMedium
Question
The number of the real solutions of the equation : $x|x + 3| + |x - 1| - 2 = 0$ is
Options
A.3
B.2
C.5
D.4
Solution
Sol.
I)
$$\begin{matrix} & x^{2} + 3x + x - 1 - 2 = 0 \\ & x^{2} + 4x - 3 = 0 \\ & x = - 2 + \sqrt{7}(\text{~}\text{rejected}\text{~}), - 2 - \sqrt{7}(\text{~}\text{rejected}\text{~}) \end{matrix}$$
II)
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