Quadratic EquationHard
Question
The number of the real solutions of the equation : $x|x + 3| + |x - 1| - 2 = 0$ is
Options
A.3
B.2
C.5
D.4
Solution
Sol.
I)
$$\begin{matrix} & x^{2} + 3x + x - 1 - 2 = 0 \\ & x^{2} + 4x - 3 = 0 \\ & x = - 2 + \sqrt{7}(\text{~}\text{rejected}\text{~}), - 2 - \sqrt{7}(\text{~}\text{rejected}\text{~}) \end{matrix}$$
II)
Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
The roots of the equation (x + 2)2 = 4 (x + 1) − 1 are -...x1 and x2 are the roots of equation ax2 + bx + c = 0 (Where a, b, c ∈ R) and x1x2 < 0, then roots of the equati...Let a > 0, b > 0 and c > 0. Then, both the roots of the equation ax2 + bx + c = 0....The equation x - has...The roots of Quadratic equation x2 + 14x + 45 = 0 are -...