General Organic ChemistryHard
Question
Arrange the following carbanions in the decreasing order of stability
I. $p - Br - C_{6}H_{4} - \overset{\ominus}{C}H_{2}$
II. $C_{6}H_{5} - \overset{\ominus}{\overset{\ominus}{C}}H_{2}$
III. $p - {CH}_{3}O - C_{6}H_{4} - \overset{\ominus}{\overset{\ominus}{C}}H_{2}$
IV. $p - CHO - C_{6}H_{4} - \overset{\ominus}{\overset{\ominus}{C}}H_{2}$
V. $p - {CH}_{3} - C_{6}H_{4} - \overset{\ominus}{\overset{\ominus}{C}}H_{2}$
Choose the correct answer from the options given below :
Options
A.I $>$ II $>$ IV $>$ V $>$ III
B.I $>$ IV $>$ II $>$ V $>$ III
C.IV $>$ I $>$ II $>$ V $>$ III
D.IV $>$ II $>$ I $>$ III $>$ V
Solution
Electron withdrawing groups increases stability of carbanion and electron donating groups decreases stability of carbanion.
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