Wave OpticsMedium
Question
When an unpolarized light falls at a particular angle on a glass plate (placed in air), it is observed that the reflected beam is linearly polarized. The angle of refracted beam with respect to the normal is $\_\_\_\_$ .
$\left( \tan^{- 1}(1.52) = {57.7}^{\circ} \right.\ $, refractive indices of air and glass are 1.00 and 1.52 , respectively)
Options
A.${39.6}^{\circ}$
B.${32.3}^{\circ}$
C.${42.6}^{\circ}$
D.${36.3}^{\circ}$
Solution
$${tani = \frac{\mu_{2}}{\mu_{1}} = \frac{\mu_{g}}{\mu_{a}} }{tani = 1.52 }{i = {57.7}^{\circ} }{r = 90^{\circ} - i }{r = {32.3}^{\circ}}$$
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