Nitrogen Containing CompoundHard

Question

Consider the following sequence of reactions.

Assuming that the reaction proceeds to completion, then 137 mg of 4-nitrotoluene will produce

$\_\_\_\_$ mg of B .

(Given molar mass in $g{mol}^{- 1}H:1,C:12,\text{ }N:14$, O : $16,Br:80$ )

Options

A.301
B.146
C.228
D.208

Solution

Mole $= \frac{137 \times 10^{- 3}}{137} = 0.001$ mole

Mole of product $= 0.001$ mole

Mass of product $= 0.001 \times 228gm$

$$= 0.228gm = 228mg$$

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