FunctionHard

Question

Let the domain of the function

$$f(x) = \log_{3}\log_{5}\left( 7 - \log_{2}\left( x^{2} - 10x + 85 \right) \right) + \sin^{- 1}\left( \left| \frac{3x - 7}{17 - x} \right| \right)$$

be $(\alpha,\beta\rbrack$. Then $\alpha + \beta$ is equal to :


Options

A.10
B.12
C.9
D.8

Solution

Let $x^{2} - 10x + 85 = \lambda$

∴ Domain for first term

$$\begin{array}{r} \lambda > 0\#(1) \end{array}$$

$$\begin{aligned} & 7 - \log_{2}\lambda > 0 \Rightarrow \lambda < 2^{7}\#(2) \end{aligned}$$

$$\begin{aligned} & \log_{5}\left( 7 - \log_{2}\lambda \right) > 0 \Rightarrow \lambda < 2^{6}\#(3) \end{aligned}$$

∴ from (1), (2) & (3)

$${0 < \lambda < 2^{6} }{0 < x^{2} - 10x + 85 < 64}$$

$$\begin{array}{r} \Rightarrow x \in (3,7)\#(A) \end{array}$$

& domain for second term $- 1 \leq \frac{3x - 7}{x - 17} \leq 1$

$$\begin{array}{r} \Rightarrow x \in \lbrack - 5,6\rbrack\#(B) \end{array}$$

From (A) & (B), domain of function will be ( 3,6 ]

$${\Rightarrow \alpha = 3,\beta = 6 }{\Rightarrow \alpha + \beta = 9}$$

Create a free account to view solution

View Solution Free
Topic: Function·Practice all Function questions

More Function Questions