Chemical BondingHard

Question

Among $H_{2}\text{ }S,H_{2}O,{NF}_{3},{NH}_{3}$ and ${CHCl}_{3}$, identify the molecule $(X)$ with lowest dipole moment value. The number of lone pairs of electrons present on the central atom of the molecule $(X)$ is :

Options

A.2
B.0
C.1
D.3

Solution

Molecule/Dipole moment

$H_{2}\text{ }S$ /0.95

$H_{2}O$ /1.85

${NF}_{3}$/0.23 (minimum)

${NH}_{3}$/1.47

${CHCl}_{3}$ /1.04

Number of lone pair on central atom $= 1$

Create a free account to view solution

View Solution Free
Topic: Chemical Bonding·Practice all Chemical Bonding questions

More Chemical Bonding Questions